BestLightNovel.com

How to Teach Part 22

How to Teach - BestLightNovel.com

You’re reading novel How to Teach Part 22 online at BestLightNovel.com. Please use the follow button to get notification about the latest chapter next time when you visit BestLightNovel.com. Use F11 button to read novel in full-screen(PC only). Drop by anytime you want to read free – fast – latest novel. It’s great if you could leave a comment, share your opinion about the new chapters, new novel with others on the internet. We’ll do our best to bring you the finest, latest novel everyday. Enjoy

Sum = is the sign commonly used to indicate the algebraic sum (_i.e._ the difference between the sum of the minus quant.i.ties and the plus quant.i.ties).

_x y _= products of deviation in one trait multiplied by deviation in the other trait with appropriate sign.

Applying the formula we find: =================================================================== |ARITH-| | | SPEL- | | | | |METIC | x | x^2 | LING | y | y^2 | xy | --+------+---+------------+-------+---+-------------+-------------+ A | 1|-3 | 9| 2|-6 | 36| +18| B | 2|-2 | 4| 4|-4 | 16| +8| C | 3|-1 | 1| 6|-2 | 4| +2| D | 4| 0 | 0| 8| 0 | | | E | 5|+1 | 1| 10|+2 | 4| +2| F | 6|+2 | 4| 12|+4 | 16| +8| G | 7|+3 | 9| 14|+6 | 36| +18| | ___| | __| ___| | ___| __| | 7 |28| |Sum x^2 = 28| 7 |56| |Sum y^2 = 112|Sum xy = +56| |Av. =4| | |Av. =8 | | | | =================================================================== Sum x y +56 +56 r = ---------------------------- = --------------------- = ---- = +1 (sqrt(Sum x^2)(sqrt(Sum y^2) (sqrt(28))(sqrt(112)) 56

If instead of achievement in one field being positively related (going together) in the highest possible degree, these individuals show the opposite type of relations.h.i.+p, _i.e.,_ the maximum negative relations.h.i.+p (this might be expressed as opposition--a place above the average in one achievement going with a correspondingly great deviation below the average in the other achievement), then our coefficient becomes -1.

Applying the formula:

=================================================================== |ARITH-| | | SPEL- | | | | |METIC | x | x^2 | LING | y | y^2 | x*y | --+------+---+------------+-------+---+-------------+-------------+ A | 1|-3 | 9| 14|+6 | 36| -18| B | 2|-2 | 4| 12|+4 | 16| -8| C | 3|-1 | 2| 10|+2 | 4| -2| D | 4| 0 | | 8| 0 | | | E | 5|+1 | 2| 6|-2 | 4| -2| F | 6|+2 | 4| 4|-4 | 16| -8| G | 7|+3 | 9| 2|-6 | 36| -18| | ___| | __| ___| | ___| __| | 7 |28| |Sum x^2 = 28| 7 |56| |Sum y^2 = 112|Sum xy = -56| |Av. =4| | |Av. =8 | | | | ===================================================================

It will be observed that in this case each plus deviation in one achievement is accompanied by a minus deviation for the other trait; hence, all of the products of _x_ and _y_ are minus quant.i.ties. (A plus quant.i.ty multiplied by a plus quant.i.ty or a minus quant.i.ty multiplied by a minus quant.i.ty gives us a plus quant.i.ty as the product, while a plus quant.i.ty multiplied by a minus quant.i.ty gives us a minus quant.i.ty as the product.)

(Sum xy) -56 -56 r = ------------------------------ = ------------------- = ---- = -1.

(sqrt(Sum x^2))(sqrt(Sum y^2)) (sqrt(28)sqrt(112)) = 56

If there is no relations.h.i.+p indicated by the measures of achievements which we have found, then the coefficient of correlation becomes 0. A distribution of scores which suggests no relations.h.i.+p is as follows:

================================================================= |ARITH- | | | | | | |METIC | x | x^2 |Spelling | y | y^2 | x.y --+-------+----+-----------+---------+----+-------------+-------- | | | | | | | - + A | 2 | -2 | 4 | 12 | +4 | 16 | -8 +6 B | 1 | -3 | 9 | 8 | 0 | | 0 +4 C | 4 | 0 | | 2 | -6 | 36 | 0 +4 D | 5 | +1 | 1 | 14 | +6 | 36 | -6 E | 3 | -1 | 1 | 4 | -4 | 16 | -14 +14 F | 7 | +3 | 9 | 6 | -2 | 4 | G | 6 | +2 | 4 | 10 | +2 | 4 | | ____| | | ___ | | | | |28 | |Sum x^2=28 | 7|56 | | Sum y^2=112 | xy=0 | AV.=4 | | | AV.=8 | | | ===================================================================

(Sum xy) 0 r = ---------------------------- = ------------------- = 0.

(sqrt(Sum x^2)sqrt(Sum y^2)) (sqrt(28)sqrt(112))

In a similar manner, when the relations.h.i.+p is largely positive as would be indicated by a displacement of each score in the series by one step from the arrangement which gives a +1 coefficient, the coefficient will approach unity in value.

=============================================================== ARITHMETIC| x | x^2 |SPELLING| y | y^2 | ---+------+----+-----------+--------+----+------------+-------- A |1 | -3 |9 |4 | -4 | 16 |+ 12 B |2 | -2 |4 |2 | -6 | 36 |+ 12 C |3 | -1 |1 |8 | 0 | |+ 4 D |4 | 0 | |6 | -2 | 4 |+ 4 E |5 | +1 |1 |12 | +4 | 16 |+ 18 F |6 | +2 |4 |10 | +2 | 4 |Sxy=50 G |7 | +3 |9 |14 | +6 | 36 | |Av. =4| |Sum x^2 =28|Av. = 8 | |Sum y^2= 112| ===============================================================

Sum xy +50 r= -------------------------- = ---- = +.89.

sqrt(Sum x^2)sqrt(Sum y^2) 56

Other ill.u.s.trations might be given to show how the coefficient varies from + 1, the measure of the highest positive relations.h.i.+p (going together) through 0 to -1, the measure of the largest negative relations.h.i.+p (opposition). A relations.h.i.+p between traits which we measure as high as +.50 is to be thought of as quite significant. It is seldom that we get a positive relations.h.i.+p as large as +.50 when we correlate the achievements of children in school work. A relations.h.i.+p measured by a coefficient of .15 may _not_ be considered to indicate any considerable positive or negative relations.h.i.+p. The fact that relations.h.i.+ps among the achievements of children in school subjects vary from +.20 to +.60 is a clear indication of the fact that abilities of children are variable, or, in other words, achievement in one subject does not carry with it an _exactly corresponding_ great or little achievement in another subject. That there is some positive relations.h.i.+p, _i.e.,_ that able pupils tend on the whole to show all-round ability and the less able or weak in one subject _tend_ to show similar lack of strength in other subjects, is also indicated by these positive coefficients.

QUESTIONS

1. Calculate the median point in the following distribution of eighth-grade composition scores on the Hillegas scale.

Quality 0 18 26 37 47 58 67 Frequency 2 68 73 3

2. Calculate the median point in the following distribution of third-grade scores on the Woody subtraction scale.

No. problems 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 Frequency 2 2 2 3 3 5 4 5 8 16 16 16 23 20 21 11 22 11 2

22 23 24 + 1

3. Compare statistically the achievements of the children in two eighth-grade cla.s.ses whose scores on the Courtis addition tests were as follows:

Cla.s.s A--6, 5, 8, 9, 7, 10, 13, 4, 8, 7, 8, 7, 6, 8, 15, 6, 7, 0, 6, 9, 5, 8, 7, 10, 8, 4, 7, 8, 6, 9, 5, 7, 2, 6, 8, 5, 7, 8, 7, 8, 5, 8, 10, 6, 3, 6, 8, 17, 5, 7.

Cla.s.s B--10, 4, 8, 13, 11, 9, 8, 10, 7, 9, 11, 10, 18, 7, 12, 9, 10, 8, 11, 10, 12, 9, 2, 11, 8, 10, 9, 14, 11, 7, 10, 12, 10, 6, 11, 8, 10, 9, 10, 17, 8, 11, 9, 7, 9, 11, 8, 12, 9, 13.

4. If the marks received in algebra and in geometry by a group of high school pupils were as given below, what relations.h.i.+p is indicated by the coefficient of correlation?

|GEOMETRY |ALGEBRA |MARKS |MARKS 1. |80 |60 2. |68 |73 3. |65 |80 4. |96 |80 5. |59 |62 6. |75 |65 7. |90 |75 8. |86 |90 9. |52 |63 10. |70 |55 11. |63 |54 12. |85 |95 13. |93 |90 14. |87 |70 15. |82 |68 16. |79 |75 17. |78 |86 18. |79 |75 19. |82 |60 20. |70 |82 21. |52 |86 22. |94 |85 23. |72 |73 24. |53 |62 25. |94 |85

5. Compare the abilities of the 10-year-old pupils in the sixth grade with the abilities of the 14-year-old pupils in the same grade, in so far as these abilities are measured by the completion of incomplete sentences.

(Note: 5 = 5.0-5.999.)

================================================== NO. SENTENCES | | COMPLETED | 10-YEAR-OLDS | 14-YEAR-OLDS --------------+--------------+-------------------- 24 |-- |-- 23 |-- |-- 22 |-- |-- 21 |1 |-- 20 |-- |-- 19 |-- |-- 18 |-- |-- 17 |-- |1 16 |3 |-- 15 |-- |2 14 |7 |4 13 |10 |3 12 |18 |7 11 |9 |10 10 |7 |9 9 |8 |10 8 |2 |10 7 |3 |10 6 |-- |2 5 |2 |3 4 |-- |2 3 |-- |-- 2 |-- |1 1 |-- |-- 0 |-- |-- ===========================================

6. From the scores given here, calculate the relations.h.i.+p between ability to spell and ability to multiply. Use the average as the central tendency.

============================== PUPIL|SPELLING|MULTIPLICATION -----+--------+--------------- A |9 |22 B |10 |16 C |2 |19 D |6 |14 E |13 |24 F |8 |22 G |10 |17 H |7 |20 I |3 |21 J |2 |21 K |14 |20 L |8 |18 M |7 |23 N |11 |25 O |8 |25 P |17 |24 Q |10 |21 R |4 |16 S |9 |15 T |6 |19 U |12 |22 V |14 |19 W |8 |17 X |3 |20 Y |11 |18 ==============================

Please click Like and leave more comments to support and keep us alive.

RECENTLY UPDATED MANGA

How to Teach Part 22 summary

You're reading How to Teach. This manga has been translated by Updating. Author(s): George Drayton Strayer and Naomi Norsworthy. Already has 952 views.

It's great if you read and follow any novel on our website. We promise you that we'll bring you the latest, hottest novel everyday and FREE.

BestLightNovel.com is a most smartest website for reading manga online, it can automatic resize images to fit your pc screen, even on your mobile. Experience now by using your smartphone and access to BestLightNovel.com